In alot of GunZ dll sources, where the dll is injected directly into Gunz, most of them edit directly to a hex value.
Ex.
Code:
#define HP_LOCK 0x4862c9
...
if(GetAsyncKeyState('H')&0x8000){if (h){ h=0;if(b)MessageBeep(MB_OK);}else{ h=1;if(b)MessageBeep(MB_ICONEXCLAMATION);} *(BYTE*)HP_LOCK ^= 8;}Ye,
since the DLL is injected to enemy's process u can read & write directly to it without ReadProcessMemory & WriteProcessMemory.
eg.
Code:
BYTE *addr = 0x4862c9; BYTE value = *addr; // read it *value = 10; //write it
process space, you may have porblems depending on the protection of that particular page. You need to use the VirtualQuery() function to see if you have read/write access to that address. Okay thanks. You were just a little off, cause your code gave me errors.
I just did some testing on it. I manipulated simple and complex variables. MSVC++ 2005
VarAddr.h
Code:
#ifndef VAR_H #define VAR_H #include#include #include #include using namespace std; #endif
Code:
#include "VarAddr.h"
int main()
{
string f;
string g = "Hello.";
int x;
int y = 111;
char n;
cout << "The size of integers on this compiler is " << sizeof(x) << " bytes." << "n";
cout << "The value of 'y' is " << y << ", its memory address is " << &y << endl;
int addr = 0x0012FED4; //(int)&y; On My Computer this is the address of y, it really equals &y
BYTE value = *(BYTE*)addr; // read it
int old = value;
*(BYTE*)addr = 123; //write it
cout << "The value of 'y' was " << old << " and is now " << y << ", its memory address is " << &y << endl;
cout << "----------------------------------------" << endl;
cout << "The size of strings on this compiler is " << sizeof(f) << " bytes." << "n";
cout << "The value of 'g' is '" << g.c_str() << "', its memory address is " << &g << endl;
int saddr = 0x0012FEEC; //(int)&g; On My Computer this is the address of g, it really equals &g
//BYTE svalue = *(BYTE*)saddr; // read it
string sold = *(string*)saddr;
*(string*)saddr = "Good Bye."; //write it
cout << "The value of 'g' was '" << sold.c_str() << "' and is now '" << g.c_str() << "', its memory address is " << &g << endl;
cout << "Press enter to exit.";
n = getch();
return 0;
}
The compiler sees 0x4862c9 as just an int (or BYTE); in trying to assign it to a pointer type it will flag it as a type mismatch.
The solution is to explicitly cast the number to a pointer:
Code:
int *addr = (int *)0x4862c9;
Code:
BYTE *addr = (BYTE *)0x4862c9;
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